(8x^2+4x+10)=(2x-9)

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Solution for (8x^2+4x+10)=(2x-9) equation: 



(8x^2+4x+10)=(2x-9)

We move all terms to the left:

(8x^2+4x+10)-((2x-9))=0

We get rid of parentheses

8x^2+4x-((2x-9))+10=0



We calculate terms in parentheses: -((2x-9)), so:

(2x-9)

We get rid of parentheses

2x-9

Back to the equation:

-(2x-9)



We get rid of parentheses

8x^2+4x-2x+9+10=0

We add all the numbers together, and all the variables

8x^2+2x+19=0

a = 8; b = 2; c = +19;
Δ = b2-4ac
Δ = 22-4·8·19
Δ = -604
Delta is less than zero, so there is no solution for the equation

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